(2x-1)^2+4x=4x(x-3)+25

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Solution for (2x-1)^2+4x=4x(x-3)+25 equation: 



(2x-1)^2+4x=4x(x-3)+25

We move all terms to the left:

(2x-1)^2+4x-(4x(x-3)+25)=0

We add all the numbers together, and all the variables

4x+(2x-1)^2-(4x(x-3)+25)=0



We calculate terms in parentheses: -(4x(x-3)+25), so:

4x(x-3)+25

We multiply parentheses

4x^2-12x+25

Back to the equation:

-(4x^2-12x+25)



We get rid of parentheses

-4x^2+4x+(2x-1)^2+12x-25=0

We add all the numbers together, and all the variables

-4x^2+16x+(2x-1)^2-25=0

We move all terms containing x to the left, all other terms to the right

-4x^2+16x+(2x-1)^2=25

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